3(2x^2-1)=8x

Solution for 3(2x^2-1)=8x equation:

3(2x^2-1)=8x

We move all terms to the left:

3(2x^2-1)-(8x)=0

We add all the numbers together, and all the variables

-8x+3(2x^2-1)=0

We multiply parentheses

6x^2-8x-3=0

a = 6; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·6·(-3)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{34}}{2*6}=\frac{8-2\sqrt{34}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{34}}{2*6}=\frac{8+2\sqrt{34}}{12}
$